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ChemMang
11-07-02 02:08
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<a href="https://www.the-hive.ws/forum/showflat.pl?Number=377186&page=53&view=&sort=5&Search=&vc=&new=&start=0&xrated=y&&URLForums=" title="Click here to show this downrated post">Br2 from Sodium Bromide + Hydrogen Peroxide</a>
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<i title="This post has been downrated by the moderators">(Rated as: UTFSE!)</i>
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Chromic<br>
<i>(<span title="The user's title at the time of posting">Synaptic Self-Mutilator</span>)</i><br>
<span title="Posting date">11-07-02 02:57</span><br>
<span title="Link to this post by using the markup [377198]">No 377198</span><br>
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<b title="The subject of this post">Bromination details</b>
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This question isn't an easy one to get an answer to. Although the answer is in TFSE, it's buried. I'll do a quick write-up:<br><br>Add 1 mol 2C-H & 0.5L AcOH in a flask. To another flask add 1.2L AcOH, 0.4L water, 118g H2SO4 (1.2mol), 142g KBr (1.2mol) & 58.3g 35% H2O2 (0.6mol). The KBr / H2SO4 / water / AcOH solution will turn from colorless solution to a golden orange-red solution on addition of H2O2 and will pick up the smell of something resembling bleach. Cool freebase in an ice-bath, drip in the Br2 solution. Then drip in 58.3g 35% H2O2 (0.6mol). Work up as usual and get your product.<br><br>The overall reaction is:<br><br>2C-H + H2O2 + KBr + H+ ==> 2C-B + 2 H2O + K+<br><br>I hate to say it, but quite honestly, if you have to ask these questions I doubt you'll be able to have enough know-how to obtain the precursors and complete the reaction as simple as it may be.<br><br>Good luck ... and KEEP STUDYING!!!
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