04-25-03 15:55
No 429331
I was just wondering if methylenation of allylbenzene is possible, like with catechol, or must it have two OH groups? Or, will the methylenedioxyallylbenzene have to be made from allylcatechol?
Love my country, fear my government.
(Chief Bee)
04-25-03 20:52
No 429373
Bwiti... You really should know better than to ask that! Of course you need allylcatechol, there is no way you can add oxygen groups like that to alkylbenzenes...
(Hive Addict)
04-25-03 22:08
No 429384
Come on man!!! Do I need to take you back to school?
[allcaps]MASSIVE FLAMING[/allcaps]
Bwiti, pm me. I've got a question for you. (unrelated to the above)
(Hive Addict)
04-26-03 04:47
No 429451
*WARNING: Question with no theoretical background whatsoever*
What if someone was to para-brominate allylbenzene, or even methamphetamine? Then couldn't the Cu powder and NaOH procedure be used on that to make a -OH substituted allyl benzene or amphetamine? Then if you were to brominate again, would it result in a single bromination right next to the -OH group? If it did, it wouldn't matter what side of the -OH it was on, and then maybe the Cu powder and NaOH again, then methylenation?
Sorry if this is completely wrong, I warned you I have no technical basis for the questions, it was just a thought.
It is seductive, way too seductive. -Eleusis
(Chief Bee)
04-26-03 18:39
No 429591
You cannot do that, the side-chain will react.
(Hive Addict)
04-27-03 01:55
No 429654
Shit, I forgot about that double bond. But what about just plain old methamphetamine, or amphetamine? The Br won't replace the amine group, will it?
It is seductive, way too seductive. -Eleusis
(PVC-Analog Taste-Tester)
04-27-03 18:33
No 429769
Oops! Sorry about that. I shall bow-out, and do the right thing.
Love my country, fear my government.