psyloxy
(Hive Addict) 10-14-03 19:21 No 464600 |
polyphosphoric acid experiences ? | Bookmark | ||||||
Uhhm, this may seem a bit pathetical, but my great interest in the subject gently forces me to post this nonetheless: I want to hear peoples voices on failed and/or successful attempts or some detailed 2nd hand writeups on preparations of the title compound (best without using P2O5) cause it is another important puzzle-piece in the picture showing the clandestine way to EtNO2 / propiophenones. Post 377568 (FriendlyFinger: "I want to make proipiophenone", Methods Discourse) Post 463377 (psyloxy: "alpha-bromopropanoic acid - a final word ?", Chemistry Discourse) Notes for it's preparation can be found in Post 398338 (Aurelius: "repost", Methods Discourse) Post 412338 (Aurelius: "Ulmann's Polyphosphoric acid", Methods Discourse) Post 362697 (starlight: "not sure as yet", Newbee Forum). I know there's lot's of refs that I could all read myself but I simply don't have easy access to them, thanks for your undestanding. --psyloxy-- |
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roger2003 (Hive Bee) 10-14-03 19:42 No 464602 |
Polyphosphoric Acid (Rated as: good read) |
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From Merck 13th: Literature References: May be prepd by heating H3PO4 with sufficient phosphoric anhydride to give the resulting product an 82-85% P2O5 content: Bell, Ind. Eng. Chem. 40, 1464 (1949); Van Wazer, Holst, J. Am. Chem. Soc. 72, 639 (1950); Kennard, Org. Chem. Bull. 29, no. 1 (1957). Consists of about 55% tripolyphosphoric acid, the remainder being H3PO4 and other polyphosphoric acids. Typical analysis: 83.0% P2O5; ortho equivalent 115.0%. roger2003 |
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Rhodium (Chief Bee) 10-16-03 09:57 No 464933 |
Preparation of Polyphosphoric Acid (Rated as: excellent) |
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Structure and Properties of the Condensed Phosphates. I. Some General Considerations about Phosphoric Acids John R. Van Wazer, Karl A. Holst J. Am. Chem. Soc. 72, 639-644 (1950) (../rhodium/pdf /polyphosphor May be prepd by heating H3PO4 with sufficient {P2O5} to give the resulting product an 82-85% P2O5 content For calculating the needed amounts, assume that 85% H3PO4 is a mixture of 15 wt% H2O and 85 wt% of a 19:81 mixture of H2O/P2O5 - This as phosphorous pentoxide and water reacts to form phosphoric acid as follows: 3 H2O (18g/mol) + 2 P2O5 (142 g/mol) 2 H3PO4 (169 g/mol) We can then calculate that 85% H3PO4 is equal to a mixture of 15 + (0.85 * 19) = 31.15 wt% H2O and 0.85 * 81 = 68.85% P2O5 Now simply add enough P2O5 to make a 82-85% solution and heat as in the article linked above. |
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