12cheman12 (Hive Bee)
09-07-04 10:07
No 530084
       Pseudo FB and HCL mole ratios     

HCL mole weight is 36.47
and one mole of pseudoephedrine weighs 165.23 (not to sure if this weight is the freebase or hcl form though)

Does this mean if i had 165.23 grams of pseudo FB i would need 36.47 grams of HCL to turn the pseudo back to hydrochloride form in a perfect ratio?
Your an individual just like everyone else 		 
 
 
 
    ozmosis
(Newbee)
09-07-04 10:37
No 530085
       "Pseudo FB and HCL mole ratios"     

pseudo freebase=165.232 and is ~80% weight of the hcl salt

does seem a little mind boggling though doesn't it 		 
 
 
 
    12cheman12
(Hive Bee)
09-07-04 11:04
No 530090
       165(pseudo FB)/ 16.5 = 10gs 36(hcl)/16.5 =...     

165(pseudo FB)/ 16.5 = 10gs
36(hcl)/16.5 = 2.8gs

So does this mean if i had 10Gs of pseudo FB i would need 2.8 Gs of HCL?

And if my HCL is 30% i would need 9.3 mls?

its not really the maths im worried about i just want to know if you need equal molar ratios when titrating so that there wont be any excess hcl.
Your an individual just like everyone else 		 
 
 
 
    placebo
(arrogant bee of the day)
09-07-04 11:17
No 530091
       yes     

yes
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    WizardX
(Wizard Master)
09-07-04 12:34
No 530103
       EPHEDRINE HCl, C10H15NO.HCl     

EPHEDRINE HCl, C10H15NO.HCl molecular weight  MW = 201.73 grams/mole

EPHEDRINE FREEBASE, C10H15NO molecular weight  MW = 165.23 grams/mole
The freebase has a melting point 40 deg C with a ½ H2O. The boiling point is 225 deg C.

-----------------------------------------------------------------------------------------
(165.23/201.73) x 100 = 81.9% is EPHEDRINE of the EPHEDRINE HCl
(36.5/201.73) x 100 = 18.1%  is HCl of the EPHEDRINE HCl
-----------------------------------------------------------------------------------------

81.9% + 18.1% = 100% or 165.23 + 36.5 = 201.73 for EPHEDRINE HCl, C10H15NO.HCl 		 
 
 
 
    BullwinkleMoose
(Newbee)
09-08-04 07:50
No 530272
       Compensating to maintain ratios for FB Pseudo E     

Compensate in your E's weight to maintain the ratios !
" Pseudo HCl is about 202gr per mole and psuedo free base is about 166gr per mole.

So 166 divided by 202 is a ratio of 0.82 FB E 

( because less weight is more E with the fb )

FBE = .82
I = 1.2
LGRP = .33

which equals

FBE = 1
I = 1.45
LGRP = .4

Hydrochloride E
HCL E = 1
I = 1.2
LGRP = .33
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