11-03-01 13:39
No 232724
in the cat faq 2.2, it told about oxydising pseudoephedrine with kmno4.
But i would use pseudo HCl, then, i calculated :
3gm(that's what i use)/201,69(mw of pseudo HCl) =0,0148mol(of pseudo HCl)
0,0148/2,5 (2,5 mole of kmno4 oxydise 1 mole of pseudo)=5,9E-3
5,9E-3*158(MW of KMnO4)=0,94g !!!
It means that i should use 0,94 g of KMnO4 if i use pseudo HCl instead of 1,148g if i use pseudoephedrine base...
please, tell me if i'm wrong because this could be the reasons of my nightmares.
skanic
(Stoni's sexual toy)
11-03-01 13:42
No 232727
> 0,0148/2,5 (2,5 mole of kmno4 oxydise 1 mole of pseudo)=5,9E-3
That's wrong. Should be 0.0148 x 2.5
(Stranger)
11-04-01 10:43
No 233020
OH shit !
excuse me for that typo error, it sould be :
"1 mole of KMnO4 oxydises 2,5 moles of pseudo" ; But the problem stays the same and it's still
0,0148/2,5=5,9E-3
Skanic
sorry for that error...